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Date Posted: Thursday, November 27 2008, 3:41:27
Author: FRed
Subject: Re: mercury lens floation
In reply to: Michael 's message, "Re: mercury lens floation" on Wednesday, November 26 2008, 6:49:57

Going back to Bobs original question of 4.5 tons of lens and 1.5 tons of mercury.

Very simplistic,but something I could place on my webpage!

Taking Archimedes that if it floats it diplaces it's own weight.

If we take a container holding 6 tons of mercury and float the lens in it,it will displace 4.5 tons of mercury-leaving 1.5 tons supporting the lens.

The 1.5 tons or X litres being the amount required to give enough flotation to allow the lens to revolve?

Michael gave the amount for a particular shape and depth,but I am after an explanation without using formula.

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