Re: Physics question -- �E�ٰ�

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Subject: Re: Physics question
Author: ...	[ Next Thread \| Previous Thread \| Next Message \| Previous Message ] Date Posted: 15:20:45 05/09/05 Mon In reply to: F.3 's message, "Physics question" on 13:31:50 05/09/05 Mon [ Next Thread \| Previous Thread \| Next Message \| Previous Message ]

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[> Subject: Re: Physics question

Author:
HKU
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Date Posted: 17:29:17 05/09/05 Mon

The weight of the iceberg is
Wi=di��Vi��g
where Vi and di are the volume and the density of the iceberg respectively.
The volume of the submerged portion of the iceberg relates to the buoyant force
F=dw��Vw��g
where Vw and dw are the volume and the density of water which is displaced by the iceberg.

At equilibrium, the upward and downward forces balance each other
F = Wi.
Hence, dw��Vw��g=di��Vi��g and we obtain the volume ratio
di/dw=Vw/Vi