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Subject: Using Carpoutput to Pass Feed

Author:
Derek

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Date Posted: 11:12:04 08/02/05 Tue

(I have a background in Java, but am fairly new to php -- so if the answer should be obvious, I apologize.)

I'm trying to integrate Carp into phpwebsite because it is so much more powerful than phpwsrss (the integrated client) and gives much greater control over the output. However, whenever I run the code:

CarpConf('outputformat',2);
CarpShow('http://newsrss.bbc.co.uk/rss/newsonline_uk_edition/world/rss.xml');
$THEME['NEWSFEED'] = "<div id=\"news\">$carpoutput</div>";

I don't get any html rendered, except for

<div id="newsfeed"></div>

So, it's evident that the string-passing is working (because otherwise it would get nothing), so I can't figure out why $carpoutput doesn't contain any data from the feed. If I change carpoutput to 0, then the data appears correctly -- except that it renders at the very beginning of the generated HTML (having displayed before the HTML file). Consequently, I have to capture the output and display it at another point in the template, namely {NEWSFEED}. However, for whatever reason, $carpoutput is not displaying properly. I wondered if it wasn't a problem with passing a pointer instead of the data, but don't really know as I'm rather new to php. I tried creating a new String with the $carpoutput data, but php didn't like that much. Any ideas?

TIA,
Derek

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Replies:

Subject	Author	Date
Re: Using Carpoutput to Pass Feed	Derek	14:08:26 08/02/05 Tue