Re: Gravitation & Orbitals --

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Subject: Re: Gravitation & Orbitals

Author:
kevin pick

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Date Posted: 10:20:06 11/05/03 Wed
In reply to: Dimitry 's message, "Gravitation & Orbitals" on 18:29:58 10/07/03 Tue

>Hi, I could use some help with this question please:
>A satellite is in a circular orbit about the Earth at
the force of gravity : f=GMm/r^2
the centripetal force is always mv^2/r for circular motion

these forces must be equal...and since v=wr (w is angular frequency) and w is 2pi/T (T is the period)

you get T^2=4pi^2/(GM) r^3 ....this is known as kepler's third law

The only thing to watch out for is that r is the distance from the center of the earth.

Cheers,
Kevin
>only 100 km above the surface. What is the orbital
>period of the satellite?
>
>I guess we are suppose to use Radius of Earth
>R=6.4x10^6(m)
> Mass of Earth
>M=5.98x10^24(kg)
>
>G=6.67x10^-11((N-m^2)/kg^2))
>I've got (85 min) for the answer, Is that correct?
>
>Thank you, Dimitry

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