Re: shellsort -- SkilaboÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°askjÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ³ÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°a TÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ¶lvunarfrÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ¦ÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°i 2

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Date Posted: 02:06:00 03/20/02 Wed
Author: Hj�lmt�r
Subject: Re: shellsort
In reply to: 's message, "shellsort" on 12:57:36 03/19/02 Tue

>Af hverju er deilt me� n�u � fyrri for lykkjunni �
>program 6.5 bls 286
>for(h = 1; h<=(r-l)/9 ; h = 3 *h+1)
>
>og �� l�ka afhverju deilir�u me� 4 � lausninni �
>verkefni 5 � vikubla�i 10

�st��an fyrir deilingu me� 9 er a� for�ast �a� a� byrja me� fyrsta h-i� of n�l�gt N (e�a r-l). Ef h-gildi� er of
n�l�gt N, �� gerir fyrsta umfer�in � Shellr��uninni frekar l�ti�. Til d�mis ef N = 100 og fyrsta h = 50, �� er veri�
a� ra�a 50 hlutlistum, hverjum af st�r�inni 2. S� umfer� gefur �� frekar l�ti� af s�r og �a� v�ri betra a� hafa
fyrsta h-i� l�gra. Hversu miki� l�gra er ekki auglj�st, en � forritinu � b�kinni hafa �eir vali� a� hafa �a� � mesta
lagi 1/9 af N-inu. �g �kva� a� pr�fa a�ra t�lu hj� m�r, �g veit ekki hvort h�n er betri, en �g hef�i l�ka geta fylgt
b�kinni og nota� t.d. 9 e�a alpha*alpha.

� �llu falli �� er ekki rangt a� fara me� h-i� upp a� N (e�a r-l), en �a� er �rugglega hra�virkara a� byrja a�eins
ne�ar.

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Replies:

Re: shellsort -- No name, 09:22:03 03/20/02 Wed