Re: shellsort -- SkilaboÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°askjÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ³ÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°a TÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ¶lvunarfrÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ¦ÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°i 2

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Date Posted: 09:22:03 03/20/02 Wed
Author: No name
Subject: Re: shellsort
In reply to: Hj�lmt�r 's message, "Re: shellsort" on 02:06:00 03/20/02 Wed

>>Af hverju er deilt me� n�u � fyrri for lykkjunni �
>>program 6.5 bls 286
>>for(h = 1; h<=(r-l)/9 ; h = 3 *h+1)
>>
>>og �� l�ka afhverju deilir�u me� 4 � lausninni �
>>verkefni 5 � vikubla�i 10
>
>�st��an fyrir deilingu me� 9 er a� for�ast �a� a�
>byrja me� fyrsta h-i� of n�l�gt N (e�a r-l). Ef
>h-gildi� er of
>n�l�gt N, �� gerir fyrsta umfer�in � Shellr��uninni
>frekar l�ti�. Til d�mis ef N = 100 og fyrsta h = 50,
>�� er veri�
>a� ra�a 50 hlutlistum, hverjum af st�r�inni 2. S�
>umfer� gefur �� frekar l�ti� af s�r og �a� v�ri betra
>a� hafa
>fyrsta h-i� l�gra. Hversu miki� l�gra er ekki
>auglj�st, en � forritinu � b�kinni hafa �eir vali� a�
>hafa �a� � mesta
>lagi 1/9 af N-inu. �g �kva� a� pr�fa a�ra t�lu hj�
>m�r, �g veit ekki hvort h�n er betri, en �g hef�i l�ka
>geta fylgt
>b�kinni og nota� t.d. 9 e�a alpha*alpha.
>
>� �llu falli �� er ekki rangt a� fara me� h-i� upp a�
>N (e�a r-l), en �a� er �rugglega hra�virkara a� byrja
>a�eins
>ne�ar.

ok. soldi� ruglingslegt �v� � figure 6.9 � b�kinni vir�ist hann ekki deila me� 9 en svo � program 6.5 gerir hann �a�

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