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Date Posted: 12/06/25 16:15:37, Thu
Author: Basic math
Subject: The probability of all three random dancers being in separate groups is (1/3) * (2/3) * (1/3) = 2/27, equal to 7.41%
In reply to: Unfair 's message, "Is it by chance that D MCG & EL are in separate splits? Also McKF & EF, MTA & CS. Come on people open your eye" on 12/06/25 12:21:11, Thu

then you simply multiply this by the probability of 2 dancers being in 2 separate groups of 100. -> 0.4975 times 0.4975 times 0.0741% = 1.83% probability of all 3 of these events transpiring. There is a 98.17% chance that the splits were manipulated.

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  • then you simply multiply this by the probability of 2 dancers being in 2 separate groups of 100. 0.497 x 0.497 x 0.0741 = 1.83% odds of happening. There is a 98.17% probability of manipulation. -- Have a nice day, 12/06/25 16:19:02, Thu
  • Kind of like you manipulated that formula? To figure probability, you'd need to take more into account -- Nope, 12/06/25 23:13:13, Thu
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